2(2) + ( 3 - (3(4)) +2! - 2)
1 + 2 + 3...+ 6 =
Jangan ngasal
Gunakan cara
Terimakasih
yang no 2 jan cara manual
2(2) + ( 3 - (3(4)) +2! - 2)
4 + ( 3 - ( 12 ) + 2 - 2 )
4 + ( -9 + 2 - 2 )
4 + ( -7 + -2 )
4 + ( -9 )
4 - 9
-5
____________________
1 + 2 + 3...+ 6 = 21
Sn = 1/2 × n × ( n + 1 )
S6 = ½ × 6 × ( 6 + 1 )
S6 = 6/2 × ( 7 )
S6 = 3 × 7
S6 = 21
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No 1.
[tex]2(2) + (3 - (3(4)) + 2! - 2) \\ \\ 2(2) + (3 - 12) + (2 \times 1) - 2 \\ \\ 4 + (- 9 + 2 - 2) \\ \\ 4 + ( - 7 - 2) \\ \\ 4 + - 9 \\ \\ = - 5[/tex]
Jadi, 2(2) + (3(4)) + 2! -2)
= –5
_____________________
No 2.
- n = 6
[tex]1 + 2 + 3.. + 6 = \\ \\ = \frac{1}{2} \times n \: \times (n + 1) \\ \\ = \frac{1}{2} \times 6 \times \: (6 + 1) \\ \\ = \frac{1}{2} \: \times 6 \times 7 \\ \\ = \frac{1}{2} \times 42 \\ \\ = 21[/tex]
Jadi, 1 + 2 + 3.. + 6 = 21
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